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yaojialing
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Filter解决session 过期，跳转到登陆页面

    博客分类：
  • JAVA
DWRJSPStrutsJavaScriptWeb 
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环境：DWR+ Struts

配置：

1、过滤.DO请求，在web.xml中加入

 

<web-app>
  <filter>
  	<filter-name>session-timeout</filter-name>
  	<filter-class>com.manage.common.SessionFilter</filter-class>
  </filter>
  <filter-mapping>
  	<filter-name>session-timeout</filter-name>
  	<url-pattern>*.do</url-pattern>
  </filter-mapping>

 2、写过滤器Filter类

 

public void doFilter(ServletRequest request, ServletResponse response,
			FilterChain chain) throws IOException, ServletException {
		HttpServletRequest requestHttp = (HttpServletRequest) request;
		String requestURI = requestHttp.getRequestURI().toLowerCase();
		// 判断是否是首次登陆
		boolean isLogin = requestURI.indexOf("login") >= 0;
		Tsysuser tsysuser = (Tsysuser) requestHttp.getSession().getAttribute("tsysuser");
		if (!isLogin && tsysuser == null) {
			request.setAttribute("message", "登陆超时，请重新登陆！");
			RequestDispatcher requestDispatcher = request.getRequestDispatcher("/index.jsp");
			requestDispatcher.forward(request, response);
		}else{
			chain.doFilter(request, response);
		}

	}

 

3、在登陆页面index.jsp的<head></head>标签中加入

 

<script language="JavaScript"> 
	if (window != top) 
	top.location.href = location.href; 
</script>

 

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